-0.2x^2+2x-1.2=0

Solution for -0.2x^2+2x-1.2=0 equation:

-0.2x^2+2x-1.2=0

a = -0.2; b = 2; c = -1.2;
Δ = b2-4ac
Δ = 22-4·(-0.2)·(-1.2)
Δ = 3.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{3.04}}{2*-0.2}=\frac{-2-\sqrt{3.04}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{3.04}}{2*-0.2}=\frac{-2+\sqrt{3.04}}{-0.4}
$